Math Combinations/Permutations Question?

A florist has to make a floral arrangement. She has 6 banksias, 5 wattles and 4 waratahs. All the flowers of each kind are different. In how many ways can the florist make a bunch of 10 flowers if she has to use at least 3 of each kind?



I know it has been asked before but the answer given was unclear. Any help appreciated thanks

Math Combinations/Permutations Question?
First 3 positiion = Banksias

So 6 x 5 x 4 = 120



Second 3 Positions = Wattles

5 x 4 x 3 = 60



Third 3 Positions = Waratahs

So 4 x 3 x 2 = 24



120 x 60 x 24 = 172800



There must be 3 banksias, 2 wattles and 1 waratah left to take last position

therefore 6 ways to take last space



So 172800 x 6

= 1036800
Reply:3*3*3*3*3*3*3*3*3*3 = Answer
Reply:for a bunch of 10 flowers ( at least 3 from each kind of A ( 6 ), B ( 5 ). C ( 4 ) ways are = C(4,4)*C(5,3)*C(6,3)

+ C(4,3)*C(5,4)*C(6,3)

+ C(4,3)*C(5,3)*C(6,4)

= 1*10*20 + 4*5*20 + 4*10*15

= 200 + 400 + 600

= 1200 ways
Reply:permutations are an ordered set without repititions. combinations are an unordered set of unique combinations. For example, both 2,3,5 and 3,2,5 are acceptable subsets of a permutation. However, a combination considers these to be the same subset.



In your case, with the flowers, either the question is very simple and the answer is three, or it's very complex and I don't feel like getting into it.
Reply:Basically you need to determine how many combinations per type of flower there are. Then you know you can "combine" those seperate "choices"/combinations together to get your 10 flowers.



So (6 choose 3) = # of ways to arrange those 6 flowers (# of ways to combine them/choose)



Do the same for the other two groups of flowers (5 choose 3) and (4 choose 3).



Finally you need to select 1 flower. We have already choose 9 of the total 15, so 6 are left. So the last flower would be (6 choose 1) which is 6.



So the total number of ways to choose 10 flowers would be:

(6 choose 3) * (5 choose 3) * (4 choose 3) * 6

skates